(W+1)^2=2w^2-3w+7

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Solution for (W+1)^2=2w^2-3w+7 equation: 



(+1)^2=2W^2-3W+7

We move all terms to the left:

(+1)^2-(2W^2-3W+7)=0

We add all the numbers together, and all the variables

-(2W^2-3W+7)+1^2=0

We add all the numbers together, and all the variables

-(2W^2-3W+7)+1=0

We get rid of parentheses

-2W^2+3W-7+1=0

We add all the numbers together, and all the variables

-2W^2+3W-6=0

a = -2; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·(-2)·(-6)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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